Fourier transform: Difference between revisions
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==Properties== | ==Properties== | ||
Note <math>\bar{x}</math> refers to the complex conjugate | Note <math>\bar{x}</math> refers to the complex conjugate | ||
Let <math>F(s) = FFT(f(s))</math>. | |||
'''Linearity''' | |||
* <math>IFFT(f) = (1/n) \bar{FFT}(\bar{f})</math> | <math>FFT(\lambda f + g) = \lambda FFT(f) + FFT(g)</math> | ||
'''Shift''' | |||
<math>FFT(f(x-a)) = e^{-i \omega_k a} F(\omega_k)</math> | |||
* Note <math>\omega_k = 2 \pi k/N </math> | |||
'''Similarity''' | |||
<math>FFT(f(ax)) = |a|^{-1} F(s/a)</math> | |||
'''Convolution Theorem''' | |||
<math>f *g \Leftrightarrow F(s) \times G(s)</math><br> | |||
<math>f \times g \Leftrightarrow F(s) * G(s)</math> | |||
'''Parseval's Theorem''' | |||
<math>\int |f(x)|^2 dx = \int |F(s)|^2 ds</math> | |||
See [[Wikipedia: Parseval's theorem]]<br> | |||
More generally, | |||
<math>\int f(x) g^*(x) dx = \int F(s) G^*(s) ds</math> | |||
'''Autocorrelation''' | |||
<math>\int f(x') f^*(x' - x) dx' \Leftrightarrow |F(x)|^2</math> | |||
This is a case of the convolution theorem. | |||
'''IFFT''' | |||
<math>IFFT(f) = (1/n) \bar{FFT}(\bar{f})</math> | |||
'''2D FFT''' | |||
<math>FFT2(f) = FFT_{x}(FFT_{y}(f)) = FFT_{y}(FFT_{x}(f))</math> | |||
==Short-time Fourier transform== | ==Short-time Fourier transform== |
Revision as of 15:04, 12 April 2023
The Fourier transform decomposes a signal (i.e. a time series) into multiple sine and cosine waves.
Background
Suppose we have signal\(\displaystyle f(x)\).
Then the Fourier transform \(\displaystyle \hat{f}(\xi)\)is defined as:
\[\hat{f}(\xi) = \int_{-\infty}^{\infty} f(x) e^{-i2 \pi \xi x} dx\]
Recall that Euler's formula states: \(\displaystyle e^{ix} = cos(x) + i \sin(x)\). Hence, \(\displaystyle e^{-i2 \pi \xi x} = cos(-2 \pi \xi x) + i \sin(-2 \pi \xi x)\) In other words, the Fourier transform is the integral (i.e. alignment) of signal times some sine and cosine waves.
The inverse of the fourier transform is: \[f(x) = \int_{-\infty}^{\infty} \hat{f}(\xi) e^{i2 \pi \xi x} d\xi\]
Discrete Fourier Transform
A naive DFT would compute the matrix of \(\displaystyle e^{-i2 \pi \xi x}\) and multiply it with the signal. This would take \(\displaystyle \mathcal{O}(n^2)\) time.
However, most languages have an FFT library which can compute the DFT in \(\displaystyle \mathcal{O}(n \log n)\) time.
In most languages, FFT is defined as: \[A_k = \sum_{m=0}^{n-1} f(x) \exp\ \left\{ -2 \pi i \frac{mk}{n} \right\}\] and IFFT is defined as: \[a_m = \frac{1}{n} \sum_{k=0}^{n-1} \hat{f}(\xi) \exp \left\{ 2 \pi i \frac{mk}{n} \right\}\]
That the main difference between the FFT and IFFT is the negative symbol in the exponent.
You can implement IFFT as IFFT(x) = (1/len(x))*conj(FFT(conj(x)))
[1].
Properties
Note \(\displaystyle \bar{x}\) refers to the complex conjugate Let \(\displaystyle F(s) = FFT(f(s))\).
Linearity \(\displaystyle FFT(\lambda f + g) = \lambda FFT(f) + FFT(g)\)
Shift \(\displaystyle FFT(f(x-a)) = e^{-i \omega_k a} F(\omega_k)\)
- Note \(\displaystyle \omega_k = 2 \pi k/N \)
Similarity \(\displaystyle FFT(f(ax)) = |a|^{-1} F(s/a)\)
Convolution Theorem
\(\displaystyle f *g \Leftrightarrow F(s) \times G(s)\)
\(\displaystyle f \times g \Leftrightarrow F(s) * G(s)\)
Parseval's Theorem
\(\displaystyle \int |f(x)|^2 dx = \int |F(s)|^2 ds\)
See Wikipedia: Parseval's theorem
More generally, \(\displaystyle \int f(x) g^*(x) dx = \int F(s) G^*(s) ds\)
Autocorrelation \(\displaystyle \int f(x') f^*(x' - x) dx' \Leftrightarrow |F(x)|^2\) This is a case of the convolution theorem.
IFFT \(\displaystyle IFFT(f) = (1/n) \bar{FFT}(\bar{f})\)
2D FFT \(\displaystyle FFT2(f) = FFT_{x}(FFT_{y}(f)) = FFT_{y}(FFT_{x}(f))\)
Short-time Fourier transform
The STFT applies FFT using a sliding window over the signal.
This produces a matrix of FFT values over time which allow you to see how the signal is changing.
References
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- ↑ Siembida, A. (2010, March 11). How to compute the IFFT using only the forward FFT. Adam Siembida Personal Webpage. Retrieved January 24, 2023, from https://adamsiembida.com/how-to-compute-the-ifft-using-only-the-forward-fft/