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Unsupervised Learning
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Revision as of 17:58, 12 November 2019
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Line 31:
Line 31:
</math><br>
</math><br>
<math>
<math>
= \sum_{j=1}^{k} \sum_{i\mid z(i)=j} 2(x^{(i)} - \mu_{j})
=
-
\sum_{j=1}^{k} \sum_{i\mid z(i)=j} 2(x^{(i)} - \mu_{j})
= 0
</math><br>
</math><br>
<math>
<math>
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