Unsupervised Learning: Difference between revisions

Line 31: Line 31:
</math><br>
</math><br>
<math>
<math>
=  \sum_{j=1}^{k} \sum_{i\mid z(i)=j} 2(x^{(i)} - \mu_{j})
-\sum_{j=1}^{k} \sum_{i\mid z(i)=j} 2(x^{(i)} - \mu_{j}) = 0
</math><br>
</math><br>
<math>
<math>