Probability: Difference between revisions

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Let <math>g</math> be a monotonic increasing function and <math>Y = g(X)</math>.<br>
Let <math>g</math> be a monotonic increasing function and <math>Y = g(X)</math>.<br>
Then <math>F_Y(y) = P(Y \leq y) = P(X \leq g^{-1}(y)) = F_X(g^{-1}(y))</math>.<br>
Then <math>F_Y(y) = P(Y \leq y) = P(X \leq g^{-1}(y)) = F_X(g^{-1}(y))</math>.<br>
And <math>f_Y(y) = (d/dy)F_Y(y) = (d/dy) F_X(g^{-1}(y)) = f_X(g^{-1}(y)) (d/dy)g^{-1}(y)</math><br>
And <math>f_Y(y) = \frac{d}{dy} F_Y(y) = \frac{d}{dy} F_X(g^{-1}(y)) = f_X(g^{-1}(y)) \frac{d}{dy}g^{-1}(y)</math><br>
Hence:
<math display="block">
  f_Y(y) = f_x(g^{-1}(y)) \frac{d}{dy} g^{-1}(y)
</math>


==Expectation and Variance==
==Expectation and Variance==