Machine Learning: Difference between revisions

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====Hoeffding's inequality====
====Hoeffding's inequality====
Let <math>X_1,...,X_n</math> be bounded in (a,b)<br>
Let <math>X_1,...,X_n</math> be bounded in (a,b)<br>
Then <math>P(|\bar{X}-E[\bar{X}]| \geq t) \leq 2exp(-\frac{2nt^2}{(b-a)^2})</math>
Then <math>P(|\bar{X}-E[\bar{X}]| \geq t) \leq 2\exp(-\frac{2nt^2}{(b-a)^2})</math>