Newbie Programming Mistakes: Difference between revisions

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(Created page with "==Weird Syntax== ===comparison to true or false=== If you have a bool, you can just use it instead of comparing to <code>true</code> or <code>false</code>: <syntaxhighlight lang="python"> # some code which produces a bool b b = a > 5 # return b == false return not b </syntaxhighlight> Similarly, you don't need to do: <syntaxhighlight lang="python"> # Unnecessary if not b: return true else: return false </syntaxhighlight> ==Not using vectorization== If you're using...")
 
 
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If you have a bool, you can just use it instead of comparing to <code>true</code> or <code>false</code>:
If you have a bool, you can just use it instead of comparing to <code>true</code> or <code>false</code>:
<syntaxhighlight lang="python">
<syntaxhighlight lang="python">
# some code which produces a bool b
# some code which produces bool b
b = a > 5
b = a > 5
# return b == false
# return b == false
Line 19: Line 19:


==Not using vectorization==
==Not using vectorization==
If you're using a language like Python or R, you can take advantage of faster SIMD instructions by using vectorized code.
If you're using a language like Python or R, you can take advantage of faster SIMD instructions by using vectorized code.<br>
Instead of writing:
Instead of writing:
<syntaxhighlight lang="python">
<syntaxhighlight lang="python">
a = np.arange(5)
a = np.arange(5)
b = np.arange(5)
b = np.arange(5)
# Bad
c = np.zeros(5)
c = np.zeros(5)
# Bad
for i in range(len(a)):
for i in range(len(a)):
   c[i] = a[i] + 5*b[i]
   c[i] = a[i] + 5*b[i]

Latest revision as of 21:09, 10 June 2022

Weird Syntax

comparison to true or false

If you have a bool, you can just use it instead of comparing to true or false:

# some code which produces bool b
b = a > 5
# return b == false
return not b

Similarly, you don't need to do:

# Unnecessary
if not b:
  return true
else:
  return false

Not using vectorization

If you're using a language like Python or R, you can take advantage of faster SIMD instructions by using vectorized code.
Instead of writing:

a = np.arange(5)
b = np.arange(5)
# Bad
c = np.zeros(5)
for i in range(len(a)):
  c[i] = a[i] + 5*b[i]
# Good
c = a + 5*b